REALLY NEED HELP!!!!

Answer the following questions for the function f(x) = \frac{ x^3 }{ x^2 - 36 } defined on the interval [ -20, 16 ]. A. The function f(x) has vertical asympototes at____ and___ B. f(x) is concave up on the region___ to and____ to___ C. The inflection poin...

Find the smallest positive value of which satisfies -- x=4.100cos(2.800x) Give the answer to four places of accuracy._________ Remember to calculate the trig functions in radian mode.

The equation: 10(x-1)(x-2)(x-3)=1, has three real solutions a<b<c where a=____, b=___ , and c=___. Enter your answers with at least six correct digits beyond the decimal point. Hint: Ask what the solutions are if the right hand side is 0 instead of 1, and...

Can someone help me out here with these two problem? I have know idea where to start. 1)The equation: 10(x-1)(x-2)(x-3)=1, has three real solutions a<b<c where a=____, b=___ , and c=___. Enter your answers with at least six correct digits beyond the decim...

Given f''(x) = 4x - 3 and f'( -3) =2 and f( -3)=-1. Find f'(x) =______ and find f( 1) =_____

Consider the function f(x) whose second derivative is f''(x) = 8x + 4sin(x). If f(0) = 2 and f'(0) = 2, what is f(x)? I got... f'(x)=4(x^2 - cos[x]) and f(x)=(4(x^3 - 3sin[x]))/3 but it's wrong. Can anyone explain to me how to solve this.

The velocity of a car is f(t)=7t meters/second. Use a graph of f(t) to find the exact distance traveled by the car, in meters, from t = 0 to t = 10 seconds

The velocity function is v(t)= t^2-5t+ 4 for a particle moving along a line. The position function s(t) is an antiderivative of the velocity function. Find the displacement, s(6) - s(-3), by the particle during the time interval [-3,6].

Estimate the area under the graph of f(x)=3x^3+5 from x=-1 to x=4, first using 5 approximating rectangles and right endpoints, and then improving your estimate using 10 approximating rectangles and right endpoints. I'm having problem with using the midpoi...

Estimate the area under the graph of f(x)=x^2+2x from x = 4 to x = 10 using 3 approximating rectangles and left endpoints. I got 290.25 as my answer but it's wrong. Would someone explain to me how to answer this question.

THANKS YOU Reiny!!! You are a great help. Turns out my "y" was wrong but I did get the "x"

I manage to get to that point but maximizing it is the problem.

I actually got 10.811 ft

f(x)=(x^3)/(x^2-36)

This website doesn't help me in solving my question.

This website doesn't help me in solving my question.

I don't know why but the answer is wrong.

That's the problem. I have no idea. The question is exactly like i posted it here. I did the same thing but i realized i wasn't given a value of what it should equal to. I was hoping there a different way of solving this problem

Never mind i got it.