original:
y = 4 + lnx
inverse:
x = 4 + lny
solving for y
lny = x-4
y = e^(x-4)
f^-1 (x) = e^(x-4)
Given f(x)=-4+lnx; Find the inverse of f. f^-1=?
3 answers
How do you find the domain and range?
domain is your choice of x's that you can use in your equation
For logs, one of the main properties is that I can only take the log of a positive number
so for y = 4 + lnx , the domain is x > 0
however, the result of taking such logs results in any real number, so the range is y ∈ R
After taking the inverse of a function, the domain of the original becomes the range of the inverse, and the range of the original becomes the domain of the inverse.
For logs, one of the main properties is that I can only take the log of a positive number
so for y = 4 + lnx , the domain is x > 0
however, the result of taking such logs results in any real number, so the range is y ∈ R
After taking the inverse of a function, the domain of the original becomes the range of the inverse, and the range of the original becomes the domain of the inverse.
1 answer