Asked by Kid
Given any Cartesian coordinates, (x,y), there are polar coordinates (r, theta) with -pi/2 < theta <= pi/2. Find polar coordinates for the cartesian coordinates (-9, -8) and (-7, 7).
For (-9, -8), I got r = sqrt(x^2+y^2) = sqrt((-9)^2+(-8)^2) = sqrt(145) = 12.04
For (-7, 7), I got r = sqrt((-7)^2+(7)^2) = sqrt(98) = 9.90
I know I already have the correct angles for theta, which is why I didn't include it here. I just wanted to make sure my answers for "r" were right, since my online homework system was telling me they were incorrect.
For (-9, -8), I got r = sqrt(x^2+y^2) = sqrt((-9)^2+(-8)^2) = sqrt(145) = 12.04
For (-7, 7), I got r = sqrt((-7)^2+(7)^2) = sqrt(98) = 9.90
I know I already have the correct angles for theta, which is why I didn't include it here. I just wanted to make sure my answers for "r" were right, since my online homework system was telling me they were incorrect.
Answers
Answered by
Damon
might be a significant figure problem. You were given integer distances
try 12.04 is 12
and 9.9 is 10
try 12.04 is 12
and 9.9 is 10
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