From the problem, we can create two equations based on the given information:
1. The cost equation: 4a + 2.5s = 2820
(Where a is the number of adult tickets sold and s is the number of student tickets sold)
2. The quantity equation: a + s = 900
(Where a + s represents the total number of tickets sold)
To determine the number of adult and student tickets sold, we can solve this system of equations.
Georgia connections academy is selling tickets to its spring fling. Adults tickets cost $4 and student tickets cost $2.50. The school makes $2,820. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variables s for student tickets and a for adult tickets sold.
Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variables s for student tickets and a for adults tickets sold. 900 tickets are sold for the spring fling. Write an equation to represent this situation. Use the above system of equations to determine how many adult and student tickets were sold.
3 answers
Use the above system of equations to determine how many adult and student tickets were sold
To determine how many adult and student tickets were sold, we can solve the system of equations:
1. 4a + 2.5s = 2820
2. a + s = 900
We can solve this system using substitution or elimination. Let's use the substitution method.
From equation 2, we can express a in terms of s: a = 900 - s.
Substituting this value of a in equation 1:
4(900 - s) + 2.5s = 2820
3600 - 4s + 2.5s = 2820
-1.5s = -780
s = -780 / -1.5
s = 520
Substituting s = 520 in equation 2 to find the value of a:
a + 520 = 900
a = 900 - 520
a = 380
Therefore, 380 adult tickets and 520 student tickets were sold.
1. 4a + 2.5s = 2820
2. a + s = 900
We can solve this system using substitution or elimination. Let's use the substitution method.
From equation 2, we can express a in terms of s: a = 900 - s.
Substituting this value of a in equation 1:
4(900 - s) + 2.5s = 2820
3600 - 4s + 2.5s = 2820
-1.5s = -780
s = -780 / -1.5
s = 520
Substituting s = 520 in equation 2 to find the value of a:
a + 520 = 900
a = 900 - 520
a = 380
Therefore, 380 adult tickets and 520 student tickets were sold.