To represent the situation mathematically, we can set up two equations based on the information provided.
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Let \( a \) be the number of adult tickets sold and \( s \) be the number of student tickets sold.
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The total cost of all tickets sold is given by:
\[ 4a + 2.50s = 2820 \]
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It is also mentioned that a total of 900 tickets were sold:
\[ a + s = 900 \]
Now we have a system of equations:
- \( 4a + 2.50s = 2820 \)
- \( a + s = 900 \)
To solve for the number of adult and student tickets sold, we can start by isolating \( s \) in the second equation:
\[ s = 900 - a \]
Now substitute \( s \) from this equation into the first equation:
\[ 4a + 2.50(900 - a) = 2820 \]
Distributing \( 2.50 \):
\[ 4a + 2250 - 2.50a = 2820 \]
Combining like terms:
\[ (4a - 2.50a) + 2250 = 2820 \]
\[ 1.50a + 2250 = 2820 \]
Subtracting 2250 from both sides:
\[ 1.50a = 2820 - 2250 \]
\[ 1.50a = 570 \]
Dividing both sides by 1.50:
\[ a = \frac{570}{1.50} = 380 \]
Now, use the value of \( a \) to find \( s \):
\[ s = 900 - a = 900 - 380 = 520 \]
Final Answer:
- Adult tickets sold: 380
- Student tickets sold: 520