Generator is supplying power to a factory by cables of resistance 20 ohm if the generator is generating 50 kilowatt power at 5000 volt.what is the power receiver factory?

Answer 1

Power = i V
50,000 = i (5000)
i = 10 amps

Power lost = i^2 R = 100(20) = 2000 watts
so
Power received at factory = 50,000 - 2,000
= 48 kilowtts

Answer 2

50,000kese aaya

Answer 3

It is given in the question.

Answer 4

Given,
Resistance(R)=20 ohm
Volts supplied(V)=5000V
Power(P)=50kW=50,000W
We know,
P=Vi
Or, i=50,000/5000
Or, i=10 A
Power lost= i^2R
=10×10×20
=2000 W
Power recieved at the factory=(50,000-2000)W
=48000 W = 58 kW.
I think it will help.👍👍

Answer 5

Sorry. It will be 48 kW