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Sayandeep Dey
Answers (2)
Sorry. It will be 48 kW
Given, Resistance(R)=20 ohm Volts supplied(V)=5000V Power(P)=50kW=50,000W We know, P=Vi Or, i=50,000/5000 Or, i=10 A Power lost= i^2R =10×10×20 =2000 W Power recieved at the factory=(50,000-2000)W =48000 W = 58 kW. I think it will help.👍👍
