Let \( x \) be the number of free throws that Gavin made, and let \( y \) be the number of three point shots he made. We have the following information:
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Gavin made a total of 13 shots: \[ x + y = 13 \]
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The points from free throws (each worth 1 point) and three point shots (each worth 3 points) add up to 25 points: \[ x + 3y = 25 \]
Now we have a system of two equations:
- \( x + y = 13 \)
- \( x + 3y = 25 \)
We can start by solving for \( x \) in terms of \( y \) using the first equation: \[ x = 13 - y \]
Next, we substitute \( x \) into the second equation: \[ (13 - y) + 3y = 25 \]
Now, simplify and solve for \( y \): \[ 13 - y + 3y = 25 \] \[ 13 + 2y = 25 \] \[ 2y = 25 - 13 \] \[ 2y = 12 \] \[ y = 6 \]
Now that we have \( y \), we can find \( x \): \[ x = 13 - y = 13 - 6 = 7 \]
So, the number of free throws Gavin made is \( x = 7 \) and the number of three point shots he made is \( y = 6 \).
Final Answer: Gavin made 7 free throws and 6 three point shots.