Question
A particular college basketball player is a 80% free throw shooter. In a game, he took 20 free throws. Find the probability he made 18 or more of his free throws.
Answers
P(18) = .8^18 * .2^2 = ?
P(19) = .8^19 * .2 = ?
P(20) = .8^20 = ?
Either-or probability is found by adding the above three answers.
P(19) = .8^19 * .2 = ?
P(20) = .8^20 = ?
Either-or probability is found by adding the above three answers.