gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. Suppose 38.9 g of butane is mixed with 35. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits.
3 answers
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write and balance the equation:
C4H10 + 13/2 O2 >>> 4CO2 + 5H2O
so for each mole of butane, you get fur moles five moles of water.
MolesButane=38.9/molmassbutane
= 38.9/58.2
moles water= 4* above
mass water= moleswater*18 grams
C4H10 + 13/2 O2 >>> 4CO2 + 5H2O
so for each mole of butane, you get fur moles five moles of water.
MolesButane=38.9/molmassbutane
= 38.9/58.2
moles water= 4* above
mass water= moleswater*18 grams
what is the proper formula of Gaseous Butane (C4H10) reacts with Gaseous Oxygen (O2) in a combustion reaction to form Carbon dioxide Gas and Gaseous Water (Dihydrogen monoxide)?
0 answers