To find the y-intercept of Function 1, \( f(x) = 4x + 2 \), we set \( x = 0 \):
\[ f(0) = 4(0) + 2 = 2 \]
Thus, the y-intercept of Function 1 is \( (0, 2) \).
For Function 2, which is described as a diagonal line connecting two data points, without loss of generality, let's assume the data points given are \( (0, -2) \) and \( (0, 2) \). The y-intercept could be either of these values depending on the exact endpoints of the diagonal line.
Now, we're comparing:
- Function 1: \( (0, 2) \)
- Function 2: \( (0, -2) \) (assuming this is one of the data points)
In this case, the y-values are:
- Function 1: 2
- Function 2: -2
Clearly, \( -2 \) (from Function 2) is smaller than \( 2 \) (from Function 1).
Therefore, the correct response is: Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smaller value.