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Question

Use the image to answer the question.

Function 1: f(x)=4x+2

Function 2:

A diagonal line connects two data points on a coordinate plane.

Compare the two functions and identify the y-values of the y-intercepts. Which function has the smaller value?

(1 point)
Responses

Function 1: (−1,0)
; Function 2: (−1,0)
. They have identical values.
Function 1: left parenthesis negative 1 comma 0 right parenthesis ; Function 2: left parenthesis negative 1 comma 0 right parenthesis . They have identical values.

Function 1: (−2,0)
; Function 2: (2,0)
. Function 1 has the smaller value.
Function 1: left parenthesis negative 2 comma 0 right parenthesis ; Function 2: left parenthesis 2 comma 0 right parenthesis . Function 1 has the smaller value.

Function 1: (0,−2)
; Function 2: (0,2)
. Function 2 has the smaller value.
Function 1: left parenthesis 0 comma negative 2 right parenthesis ; Function 2: left parenthesis 0 comma 2 right parenthesis . Function 2 has the smaller value.

Function 1: (0,2)
; Function 2: (0,−2)
. Function 2 has the smaller value.
Function 1: left parenthesis 0 comma 2 right parenthesis ; Function 2: left parenthesis 0 comma negative 2 right parenthesis . Function 2 has the smaller value.
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Answer 1

Bot GPT 4-o mini answered
2 hours ago

To find the y-intercept of Function 1, which is given by \( f(x) = 4x + 2 \), we evaluate the function at \( x = 0 \):

\[ f(0) = 4(0) + 2 = 2 \]

So the y-intercept of Function 1 is \( (0, 2) \).

For Function 2, we don't have a specific equation, but if we assume that it connects two data points and one of them is at \( (0, -2) \), then the y-intercept would be \( (0, -2) \).

Now, comparing the y-intercepts:

Function 1: \( (0, 2) \)
Function 2: \( (0, -2) \)

The y-value of the y-intercept for Function 1 is 2, and for Function 2 it is -2.

The smaller value is from Function 2. Thus, the correct response is:

Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smaller value.