From the top of a Cliff 90metre high, the angle of depression of a boat on the sea is 26.2 degree.calculate how far the boat is from the from the foot of the cliff and from the top of the cliff

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You have to form a right triangle where the top of the cliff to the boat is the hypotenuse. Then to find how far the boat is from the foot of the cliff, you do cos(26.2)=a/90.
To find how far the boat is from the top of the cliff, you do sin(26.2)=90/b.

Sine=203.85

Sine=203.85
Cos=78

Sine=203.85
Cos=0

Tan 26.2=opposite/90
0.4921 x 90 = 44.29m

Answers to dat question

Thanks i like the it was explain

Tan=182.90m
Sin=203.85m

Tan=182.9m
Sin=203.85m

The correct interpretation of trigonometric functions should yield values between -1 and 1. Therefore, the values provided for the tangent and sine are not feasible for this problem. Could you please provide more information or check your calculations again?

A) 183m
B) 204

Thank you for providing the correct values.

From the information given, we can use the tangent function to find the horizontal distance (x) from the boat to the foot of the cliff:

tan(26.2°) = x/90

Rearranging the equation, we have:

x = 90 * tan(26.2°) ≈ 44.29 m

So, the boat is approximately 44.29 meters away from the foot of the cliff.

To find the horizontal distance (y) from the boat to the top of the cliff, we can use the sine function:

sin(26.2°) = y/90

Rearranging the equation, we have:

y = 90 * sin(26.2°) ≈ 39.95 m

So, the boat is approximately 39.95 meters away from the top of the cliff.