From the top of a building the angle of elevation of the top of a nearby building is 23 degrees and the angle of depression of the bottom of the nearby building is 52 degrees. The distance between the two buildings is 35m. What is the height of the second building?
4 answers
Nevermind, I found it..
tan 23 = top part /35
so top part = 35 tan 23
tan 52 = bottom part/35
so bottom part = 35 tan 52
so top part + bottom part = total height = 35(tan 23 +tan 52)
so top part = 35 tan 23
tan 52 = bottom part/35
so bottom part = 35 tan 52
so top part + bottom part = total height = 35(tan 23 +tan 52)
oh well :)
or, using the law of cosines,
h^2 = (35sec23°)^2 + (35sec52°)^2 - 2(35sec23°)(35sec52°)cos75°
Now, isn't that nice and simple? ...
h^2 = (35sec23°)^2 + (35sec52°)^2 - 2(35sec23°)(35sec52°)cos75°
Now, isn't that nice and simple? ...