From the Periodic table, it can be determined that iron (Fe) has an atomic mass of 56 amu, oxygen (O) has an atomic mass of 16 amu, and hydrogen (H) has a mass of 1 amu. What would the atomic mass of Fe(OH) 3 be?(1 point) Responses 75 amu 75 amu 107 amu 107 amu 73 amu 73 amu 219 amu 219 amu

Answer 1

To calculate the atomic mass of Fe(OH)₃ (iron(III) hydroxide), we need to sum the atomic masses of all the atoms in the molecule.

1. Iron (Fe): 1 atom × 56 amu = 56 amu
2. Oxygen (O): 3 atoms × 16 amu = 48 amu (since there are 3 hydroxide ions, each containing one oxygen)
3. Hydrogen (H): 3 atoms × 1 amu = 3 amu (again, each hydroxide ion contains one hydrogen)

Now, we can sum these values:

\[ \text{Total mass} = \text{mass of Fe} + \text{mass of O} + \text{mass of H} \] \[ \text{Total mass} = 56\ \text{amu} + 48\ \text{amu} + 3\ \text{amu} = 107\ \text{amu} \]

Thus, the atomic mass of Fe(OH)₃ is 107 amu.