To calculate the atomic mass of Fe(OH)₃, we need to add the atomic masses of iron (Fe), oxygen (O), and hydrogen (H) in the formula.
- The atomic mass of iron (Fe) = 56 amu.
- The atomic masses of oxygen (O) and hydrogen (H):
- Each hydroxide group (OH) contains one oxygen and one hydrogen.
- The atomic mass of oxygen (O) = 16 amu.
- The atomic mass of hydrogen (H) = 1 amu.
Since there are three hydroxide groups in Fe(OH)₃, we can find the total mass contributed by the hydroxide groups:
\[ \text{Total mass of OH groups} = 3 \times (\text{mass of O} + \text{mass of H}) = 3 \times (16 , \text{amu} + 1 , \text{amu}) = 3 \times 17 , \text{amu} = 51 , \text{amu} \]
Now, we add the mass of iron to the total mass of the hydroxide groups:
\[ \text{Total mass of Fe(OH)₃} = \text{mass of Fe} + \text{total mass of OH groups} = 56 , \text{amu} + 51 , \text{amu} = 107 , \text{amu} \]
Thus, the atomic mass of Fe(OH)₃ is 107 amu.