From 4 cans with 96 bolts in each, 3/4 of the bolts in one can are used, as are 5/8 of the bolts in a second can are used, 1/2 of the bolts in a third can, and 1/4 in the remaining can. What is the fraction of the total number of bolts remaining in these 4 cans?

Answer 1

The first can has 96 x 3/4 = <<96*3/4=72>>72 bolts used.
The second can has 96 x 5/8 = <<96*5/8=60>>60 bolts used.
The third can has 96 x 1/2 = <<96*1/2=48>>48 bolts used.
The fourth can has 96 x 1/4 = <<96*1/4=24>>24 bolts used.
So, the total number of bolts used is 72 + 60 + 48 + 24 = <<72+60+48+24=204>>204.
Therefore, the total number of bolts remaining is 4 x 96 - 204 = <<4*96-204=132>>132.
The fraction of the total number of bolts remaining is 132/4 x 96 = 33/96 = <<132/(4*96)=33/96>>11/32. Answer: \boxed{\frac{11}{32}}.