`\frac{3mn}{-2p}` when `m\ =\ \frac{1}{3},` `n\ =-3,`and `p=3.`

Answer 1

Substituting the given values, we have:

\[\frac{3mn}{-2p} = \frac{3\left(\frac{1}{3}\right)(-3)}{-2(3)} = \frac{-1\cdot(-3)}{-2\cdot3} = \frac{3}{6} = \boxed{\frac{1}{2}}.\]