Four wrestlers step on a scale for a tournament. Wrestler A weighs in at 170 pounds; wrestler B weighs in at 168 pounds; wrestler C weighs in at 171 pounds; and wrestler D weighs in at 169 pounds. Which of these wrestlers experiences the greatest force due to gravity? (1 point)

Question

Responses

Wrestler A
Wrestler A

Wrestler B
Wrestler B

Wrestler C
Wrestler C

Wrestler D
Wrestler D

Answer 1

The force due to gravity acting on an object can be calculated using the formula:

\[ F = m \cdot g \]

where \( F \) is the force, \( m \) is the mass of the object (in this case, the weight of the wrestler), and \( g \) is the acceleration due to gravity (approximately \( 9.81 , \text{m/s}^2 \) on Earth, but since we're comparing weights, we can ignore \( g \) as it is constant for all).

Since the only variable affecting the force due to gravity here is the weight of each wrestler, the wrestler with the highest weight will experience the greatest force due to gravity.

Here are the weights:

• Wrestler A: 170 pounds
• Wrestler B: 168 pounds
• Wrestler C: 171 pounds
• Wrestler D: 169 pounds

Wrestler C, weighing 171 pounds, has the greatest weight.

Therefore, the wrestler that experiences the greatest force due to gravity is Wrestler C.