Question

Four wrestlers step on a scale for a tournament. Wrestler A weighs in at 170 pounds; wrestler B weighs in at 168 pounds; wrestler C weighs in at 171 pounds; and wrestler D weighs in at 169 pounds. Which of these wrestlers experiences the greatest force due to gravity? (1 point) Responses Wrestler A Wrestler A Wrestler B Wrestler B Wrestler C Wrestler C Wrestler D/...

Answer 1

The force due to gravity on an object is calculated using the formula:

\[ F = m \cdot g \]

where \( F \) is the force, \( m \) is the mass (or weight in this case), and \( g \) is the acceleration due to gravity (approximately \( 9.81 , m/s^2 \), though it is a constant for all on Earth).

Since all wrestlers are on the same planet and thus experience the same acceleration due to gravity, the force due to gravity is directly proportional to their weights. Therefore, the wrestler with the greatest weight will experience the greatest force due to gravity.

Now, comparing the weights:

• Wrestler A: 170 pounds
• Wrestler B: 168 pounds
• Wrestler C: 171 pounds
• Wrestler D: 169 pounds

Wrestler C, weighing 171 pounds, is the heaviest.

Therefore, Wrestler C experiences the greatest force due to gravity.

So the answer is: Wrestler C.