Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.What is the mole fraction of N2 in the mixture?

8 answers

P V = n R T

V, T and R are the same for each
so
n, the number of mols is proportional to P

total pressure = 3.5 + 2.8 + .25 + .15 = 6.7
so for example mol fraction of N2 = 3.5/6.7 = .522
thank you so much you are a great help have a nice day. you are an amazing and smart person!
this doesnt help my equation lol thanks alot tho
Where, was, why the answer?
0.52
6.7 atm is the answer
What is the total pressure inside the cylinder?
6.7 atm
What is the mole fraction of N2 in the mixture?
0.52 atm
for the next half:
What is the mole fraction of O2 in the mixture? .42
What is the mole fraction of Ar in the mixture? .037