Four darts are thrown at this dartboard. If all four darts hit the board, how many different point totals are possible?

Question

there are 4 circles with point totals:
working out from the middle bulls eye..
bulls eye = 9
2nd circle = 7
3rd circle = 4
outter circle = 1

please help, i'm stuck

Answer 1

Highest four: 3 or 4 4s: 36, 34, 31, 28
Three or four 1s: 4, 7, 10, 12
Three or four 4s: 10, 11, 13, 16
Three or four 7s: 32,29,26, 23
Other possibilities: 15, 19, 20, 22, 25
Maybe I missed a few.

Answer 2

4 darts are thrown at this dart board if all 4 darts hit the board how many different points are possible bullseye 9 2nd circle 7 third circle 4 outer circle 1

Answer 3

there are 23 different point totals possible

Answer 4

23- 4,7,10,12,13,15,16,18,19,20,21,22,24, 25,26,27,28,29,30,31,32,34,36

Answer 5

Yur aye grapefroot end u are bolayang me online. My dad is miscrosoft and he can eat people if you giev the rong anser.

Answer 6

17 This is probably 100% wrong because I am only 11... the way I did this was get the 4 different numbers (1,4,7,9)and write out all the different outcomes not in the order just how many of each number in each answer then I added them all and if 2 equaled the same then I eliminated 1 of them then I counted how many of them there was and that's what I got I could of kept going with different outcomes and gotten a higher number then 17 but as you see I am only 11 and I really couldn't do anymore because i had to go to bed. That is just a strategy to use that you could do and start from scratch but continue on when at 17.
Thanks for reading
I hope I helped but I probably really didn't.
Thanks

Answer 7

I got the 24 possible combinations

24- 4,7,10,12,13,15,16,18,19,20,21,22,24,23 25,26,27,28,29,30,31,32,34,36

I include the extra number "23" from previous answer

which is the following combination (2x9) + 4 + 1 = 23.

Here are my workings

1 4 7 9 Score Darts

4 0 0 0 4 4
3 1 0 0 7 4
3 0 1 0 10 4
3 0 0 1 12 4
2 2 0 0 10 4
2 0 2 0 16 4
2 0 0 2 20 4
2 1 1 0 13 4
2 0 1 1 18 4
2 1 0 1 15 4
1 3 0 0 13 4
1 0 3 0 22 4
1 0 0 3 28 4
1 1 1 1 21 4
1 2 0 1 18 4
1 2 1 0 16 4
1 1 2 0 19 4
1 1 0 2 23 4
1 0 2 1 24 4
1 0 1 2 26 4
0 1 1 2 29 4
0 1 2 1 27 4
0 2 1 1 24 4
0 3 1 0 19 4
0 1 3 0 25 4
0 0 3 1 30 4
0 0 1 3 34 4
0 3 0 1 21 4
0 1 0 3 31 4
0 4 0 0 16 4
0 0 4 0 28 4
0 0 0 4 36 4
0 2 2 0 22 4
0 0 2 2 32 4
0 2 0 2 26 4

Answer 8

there are definitely 29 possible outcomes

Answer 9

My online maths says its 24