Four boxes of various masses are placed on a friction

Question

free table. Rank these boxes according to net force
by listing them in order from greatest to least.

A) <-5N--| 5 kg |--10N->

B) <-10N--|10kg|-15N-->

C) <-10N--|5kg|-15N-->

D) <-5N--|20kg|-15N-->

Thank You :)
(the |_ kg | are the boxes)
=)

Answer 1

With no friction, the mass in the box will not affect the net force.

D) will have a net force of 10 N to the right. All of the other three will have a net force of 5 N to the right. They would be "tied"

Answer 2

I apologize I forgot to add: which has the most force to the right?
will this still affect the answer?

Thank You

~Jill :]

Answer 3

If you read my answer (D), it will answer your latest question.

Answer 4

Ok thank you :) I didn't see the rest of the answer because it went off the page, thank you so much for your help! :)

Answer 5

What if box D is 15 kilos?