Three boxes are connected by cords, one of which (mA) wraps over a pulley having negligible friction on its axle and negligible mass and two boxes (mB & mC) are hanging. The masses are mA = 22.0 kg, mB = 40.0 kg, mC = 16.0 kg.
-When the assembly is released from rest, what is the tension in the cord that connects boxes B and C?
-How far (in meters) does box A move in the first 0.250 s (assuming it does not reach the pulley)?
Write the force equation clockwise being positive.
Ma*g-Mb*g-Mc*g=totalmass*acceleration.
where total mass is the sum of the three masses. Solve for acceleration.
Tension that connects to B is the same as the tension that is connected to A.
Ma*g-Tension=totalmass*acceleration
displacement= 1/2 acceleration*time^2
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