To find the equation for which the steps involve first dividing both sides by 6 and then adding 8 to both sides, we need to manipulate the equations accordingly.
-
6(x + 8) = 48
- Divide by 6: \( x + 8 = 8 \)
- Subtract 8 from both sides: \( x = 0 \)
- (Order does not match)
-
6(x − 8) = 48
- Divide by 6: \( x - 8 = 8 \)
- Add 8 to both sides: \( x = 16 \)
- (Order does not match)
-
6x − 8 = 48
- Add 8 to both sides: \( 6x = 56 \)
- Divide by 6: \( x = \frac{56}{6} \)
- (Order does not match)
-
8(x − 6) = 48
- Divide by 8: \( x - 6 = 6 \)
- Add 6 to both sides: \( x = 12 \)
- (Order does not match)
None of these equations match the specified order of operations (first dividing by 6 and then adding 8). However, the operation needed after division by 6 should involve a situation where adding 8 would be necessary to isolate the variable \( x \).
The correct arrangement for your specified procedure does not seem to be present directly in the provided options.
However, if we were to use the equation \( 6(x - 8) = 48 \):
-
Dividing both sides by 6 gives us:
\( x - 8 = 8 \) -
Now, adding 8 to both sides gives us:
\( x = 16 \)
This inverse operation order closely matches but still leads to solving \( x \); thus none satisfy the order you suggested.
Overall, it seems no answer aligns appropriately with the order of operations: divide, then add specifically regarding moving to the right algebraically as supplied.