We are given that 8×10^3 is 40 times larger than A ×10^2.
Mathematically, this can be represented as:
8×10^3 = 40(A ×10^2)
Simplifying the right side of the equation:
8×10^3 = 40×A×10^2
8000 = 4000A
Finally, we can solve for A by dividing both sides of the equation by 4000:
A = 8000/4000 = 2
Therefore, the value of A that satisfies the given condition is 2.
For what value of A will 8×10^3 be 40 times larger than A ×10^2 ?
3 answers
so how much larger?
To find out how much larger 8×10^3 is compared to A×10^2, we can divide 8×10^3 by A×10^2.
8×10^3 / A×10^2
Since division of exponents is subtraction of the exponents, we can rewrite the expression as:
8×10^3 / A×10^2 = (8/A) × 10^(3-2) = (8/A) × 10^1
Simplifying further:
(8/A) × 10^1 = 8/A × 10 = 80/A
Therefore, 8×10^3 is (80/A) times larger than A×10^2.
8×10^3 / A×10^2
Since division of exponents is subtraction of the exponents, we can rewrite the expression as:
8×10^3 / A×10^2 = (8/A) × 10^(3-2) = (8/A) × 10^1
Simplifying further:
(8/A) × 10^1 = 8/A × 10 = 80/A
Therefore, 8×10^3 is (80/A) times larger than A×10^2.