For the system 2A (g) + B( g) = 2C (g), if the initial concentration of pure C is 1.00 M, the equilibrium concentration is 0.40 M. What is the value of Kc?
Choose one answer.
a. 5.0
b. 0.45
c. 0.67
d. 2.2
e. 1.5
3 answers
Set up an ICE chart and solve. Post your work if you get stuck.
2A + B= 2C
I 0 0 1.00
C 2X X -2X
E 2X X 1.00-2X
KC= 0.40= C^2/ A^2*B
square root 0.40 (x*x)=1.00-2x
0.40(X)^2 SQUARE ROOT 0.40-1.00
I ended up with 0.09 but when I plugged it back in then I don't get any of the above answers. I don't know what I was doing wrong.
I 0 0 1.00
C 2X X -2X
E 2X X 1.00-2X
KC= 0.40= C^2/ A^2*B
square root 0.40 (x*x)=1.00-2x
0.40(X)^2 SQUARE ROOT 0.40-1.00
I ended up with 0.09 but when I plugged it back in then I don't get any of the above answers. I don't know what I was doing wrong.
2A + B ==> 2C
If Ceq = 0.4 and it was 1.0 initially, it must have changed by 1-0.4= 0.6
Therefore, B must have changed by +0.3 and A must hav changed by 0.6 so the final concns are
A = 0.6 M
B = 0.3 M
C = 0.4 M
Plug those in and calculate Kc.
If Ceq = 0.4 and it was 1.0 initially, it must have changed by 1-0.4= 0.6
Therefore, B must have changed by +0.3 and A must hav changed by 0.6 so the final concns are
A = 0.6 M
B = 0.3 M
C = 0.4 M
Plug those in and calculate Kc.