5.50 x 10-4
That's because for every mole of Br2 consumed you have an equal number of moles CO2 formed.
For the reaction shown below, the average rate of formation of CO2 (g) is 5.50 x 10-4 mol/L·s:
Br2 (aq) + HCOOH (aq) 🡪 2Br- (aq) + 2H+ (aq) + CO2 (g)
What is the rate at which Br2 (aq) is consumed?
1 answer