I have re-balanced your equation.
2N2O5 (g) -> 4NO2 (g) + 5O2 (g)
a)0.1 mol/s x (4 mols NO2/2 mols N2O5)
b) same process.
Consider the chemical reaction below equated
2N2O5 (g) -> 4NO2 (g) + O2 (g)
knowing that a certain period of time, N2O5 consumption rate is 0.10 mole / s, determine for the same time interval:
a) the average rate of formation of NO2
b) the average speed O2 formation
1 answer