For the reaction 2Na(s) + Cl(g) �¨2NaCl(s), how many grams of NaCl could be produced from 103.0 g of Na and 13.0 L of Cl (at STP)?

Answer 1

How many moles of Cl2 is 13L at stp?

How many moles of Na is 103g?

It appears that Cl2 is the limiting reactant, so for each mole of Cl2, you get two moles of NaCl. Take the moles of the Cl2 (if it is indeed the limiting reactant) and multiply it by 2, then convert that to grams of NaCl