For the reaction 2Na (s) + Cl2 (g) --> 2NaCl (s), how many grams of NaCl could be produced from 103.0 g of Na and 13.0 L of Cl2 (at STP)? What is the limiting reactant?

Answer 1

Convert 103.0 g Na to moles. moles = grams/molar mass
Convert 13.0L Cl2 to moles . moles = L/22.4
Using the coefficients in the balanced equation, convert moles Na to moles NaCl.
Do the same for moles Cl2 to moles NaCl.
You will obtain two different answers and both can't be right. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reagent producing the value is the limiting reagent.
grams NaCl = moles NaCl x molar mass NaCl.