Asked by Schooooool
For the reaction 2Na (s) + Cl2 (g) --> 2NaCl (s), how many grams of NaCl could be produced from 103.0 g of Na and 13.0 L of Cl2 (at STP)? What is the limiting reactant?
Answers
Answered by
DrBob222
Convert 103.0 g Na to moles. moles = grams/molar mass
Convert 13.0L Cl2 to moles . moles = L/22.4
Using the coefficients in the balanced equation, convert moles Na to moles NaCl.
Do the same for moles Cl2 to moles NaCl.
You will obtain two different answers and both can't be right. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reagent producing the value is the limiting reagent.
grams NaCl = moles NaCl x molar mass NaCl.
Convert 13.0L Cl2 to moles . moles = L/22.4
Using the coefficients in the balanced equation, convert moles Na to moles NaCl.
Do the same for moles Cl2 to moles NaCl.
You will obtain two different answers and both can't be right. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reagent producing the value is the limiting reagent.
grams NaCl = moles NaCl x molar mass NaCl.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.