Call it HP.
...............HP ==> H^+ + P^-
initial....0.186M......0....0
change........-x.......x.....x
equil.....0.186-x......x......x
Ka = (H^+)(P^-)?(HP)
Substitute from the ICE chart, solve for x = H^+ = P^-
For the ionization of phenylacetic acid,
Hc8H7O2 +H20 <--> C8H7O2- (aq) + H3o+ (aq) Ka + 4.9x10^-5
What is the concentration of the phenylacetic ion, C8H702,- in 0.186 M phenylacetic acid, HC8H702?
1 answer
1 answer