For the function f(x) = x^2 - 4x +5, x>= 2, which is equal to d/dx (f-1 this is the inverse)(x)) ?

Question

1/(2y-4) where x and y are related by the equation (satisfy the equation) x=y^2-4y+5 x>= 1

2y-4 where x and y are related by the equation y= = x^2 - 4x +5, x>= 2

1/2x-4 for x>= 1

1/2x-4 for x>= 2

1/2y-4 where x and y are related by the equation y= = x^2 - 4x +5, x>= 2

Answer 1

inverse of x^2 - 4x +5 is 2±sqrt(x-1) and the derivative of that is (2x-4) but I don't know how to get the x>= 1 or x>= 2

Answer 2

Answer is 1/(2y-4) where x and y are related by the equation (satisfy the equation) x=y^2-4y+5 x>= 1

Answer 3

The inverse function is x=y^2-4y+5
And the domain start from 1 to infinity to make one-to-one function. So, you get y' of inverse function = 1/(2y-4) where [1,infinity).