To determine which equation correctly describes the function represented in the table, we can analyze the provided \(x\) and \(y\) values:
\[ \begin{align*} x & : 0, 2, 4, 6 \ y & : -2, 4, 10, 16 \ \end{align*} \]
Let's evaluate the changes in \(y\) based on the changes in \(x\):
- When \(x = 0\), \(y = -2\)
- When \(x = 2\), \(y = 4\)
- When \(x = 4\), \(y = 10\)
- When \(x = 6\), \(y = 16\)
Now, let's find the differences between \(y\) values as \(x\) increases:
- From \(0\) to \(2\): \(4 - (-2) = 6\)
- From \(2\) to \(4\): \(10 - 4 = 6\)
- From \(4\) to \(6\): \(16 - 10 = 6\)
The difference in \(y\) is consistently \(6\) as \(x\) increases by \(2\).
Based on this, the relationship appears to be linear. To express the linear function in slope-intercept form \(y = mx + b\):
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The slope \(m\) can be calculated from the differences:
\(m = \frac{\Delta y}{\Delta x} = \frac{6}{2} = 3\)
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Now, we can determine the y-intercept by substituting one of the points into \(y = 3x + b\). Let's use the point (0, -2):
\(-2 = 3(0) + b \rightarrow b = -2\)
Thus, the linear function can be formulated as:
\[ f(x) = 3x - 2 \]
Therefore, the correct response is:
f(x) = 3x - 2