For the following reaction, how many kJ of heat are produceed in forming 225.0 g of NO?
4 NH3 + 5 O2 → 4 NO + 6 H2O
ΔHrxn = -906 kJ/mole
1 answer
Heat=-906kJ * 225/molmassNO*1/4
4 NH3 + 5 O2 → 4 NO + 6 H2O
ΔHrxn = -906 kJ/mole
1 answer