I can not see your drawing f course but assume that point C is below point E
It lost 20 Joules dropping from E to C
Its velocity at E was zero
drop in PE = gain in Ke
20 = (1/2) m v^2
so
v = sqrt(40/m)
If it gains 20 Joules of PE going back up and losing that 20 Joules of KE then point A is at the same height as point E
If you drop on your sled from the top of a hill then if the snow is frictionless you have enough kinetic energy at the bottom to make it up the next hill to the same height.
For the following questions, assume the potential
energy of the mass was 0.20 J when released at
point E.
a) If the mass-cord system loses 0.20 J of potential
energy as it travels to point C, what velocity would it
gain as it is accelerated to point C?
b) If all this kinetic energy was converted to
gravitational potential energy at its maximum height
at A, how far is point A above point C?
1 answer
1 answer