For the following equation of a hyperbola determine the center, vertices, foci, and asymptotes? 36x^2-y^2-24x+6y-41=0

Answer 1

do this just like the ellipse in your earlier post. That is, complete the squares, then review your text about hyperbolas.

36x^2-24x - (y^2-6y) = 41
36(x - 1/3)^2 - (y-3)^2 = 41 + 36/9 - 9
(x-1/3)^2 - (y-3)^2/36 = 1