For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.

Answer 1

w = wavelength
1/w = RZ^2(1/n1^2 - 1/n2^2)
R = 1.09737E7
Z = 4
n1^2= 3^2= 9
n2^2 = 4^2 = 16

Answer 2

8.56*10^6
amar chauhan

Answer 3

What are the concepts used in these?