For the curve given by 4x^2+y^2=48+2xy show that ((dy)/(dx))=(y-4x)/(y-x)

Answer 1

take the function, and do the partial..

8x dx + 2y dy = 0 + 2x dy + 2y dx

dx(8x-2y)= dy(2x-2y)

dy/dx= (4x-y)/(x-y)=(y-4x)/(y-x)