for function f(x)=4x-2x^3
a.) Find the general formula for the slope of the tangent line using the definition of derivative.
b.) Find the slope at x=1
5 answers
So for part (a), do you know how to find the derivative of f(x) = 4x-2x^3
yea I actually just figured out part a
now I just need help with b
now I just need help with b
I got f'(x)=-6x^2+4
do I just plug 1 in for x into -6x+4
You have already gotten your slope
Which is give as Δy/Δx
Just plug 1 into it and you're done
Which is give as Δy/Δx
Just plug 1 into it and you're done