You seem to have mixed up AlCl2 and the real product, AlCl3. Your equation would be balanced if you had written the aluminum chloride formula correctly.
To find out which is the limiting reactant, compute the number of moles available of each reactant. You have 0.556 moles of Al and 0.441 moles of HCl. Since there are not three times (or more) as many moles of HCl, HCl is the limiting reactant.
For each product of the following unbalanced equations which reactant is limiting, and calculate the mass of each product that is expected.
1) 2Al + 6HCL --> 2AlCl2 + 3H2
15.0gAl * 1moleAl/26.981gAl * 2moleAlCl3/2moleAl * 133.34gAlCl3/1moleAlCl3= 74.1gAlCl3
15.0gHCL * 1moleHCL/36.461gHCL * 2moleAlCl3/6moleHCL * 133.34gAlCl3/1moleAlCl3 = 18.3gAlCl3
The second equation would be the Limiting reaction. I have no clue how to solve the rest of this problem.
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