S is 1s2 2s2 2p6 3s2 3p4. You are right with either c or d. I don't know what your study guide is calling 3p1 and 3p4.
The 3p configuration is ud u u where up is the spin one way and d is spin the other way. he least amount to ionize with be the two outside (either of the 3p unpaired electrons). I would think both 3p1 and 3p4 means the u and d of the first orbital but that may not be right.
For an atom of sulfur, which electron would require the least amount of energy to remove from the atom?
A. 3s2
B. 1s1
C. 3p1
D. 3p4
I think the answer is c or d, preferring d. What would you go with?
2 answers
it is 3p4 since a sulfur atom doesnt have 3p1
1 answer