speed upwind =400-w
distance upwind = d = (400-w)(3)
down the breeze:
d+225=(400+2w)(3)
Flying against the wind, Lisa made the flight from Reno in 3 h with a steady airspeed of 400km/h. Returning later with a tail wind that had doubled in magnitude, she landed 225 km beyond the starting point in 3 h. What was the original wind speed? How far from Reno did she begin the trip?.........I know how to solve i just need the two equations.
4 answers
soo the two equations i would use
d = (400-w)(3)
d=(400+2w)(3)-225
d = (400-w)(3)
d=(400+2w)(3)-225
soo w= 25km/hr
x = speed of airplane
y = wind speed
With tailwind = 400/3 = 133.3
With headwind = 225/3 = 75
x + y = 133.3
x - y = 75
x + x + y - y = 208.3
2x = 208.3
x = 104.15
104.15 - y = 75
104.15 - 75 = y
29.15 = y
y = 29.15
The natural speed of the aircraft is 104.15km/h while the wind speed is 29.15km/h.
y = wind speed
With tailwind = 400/3 = 133.3
With headwind = 225/3 = 75
x + y = 133.3
x - y = 75
x + x + y - y = 208.3
2x = 208.3
x = 104.15
104.15 - y = 75
104.15 - 75 = y
29.15 = y
y = 29.15
The natural speed of the aircraft is 104.15km/h while the wind speed is 29.15km/h.