An airplane cruises at 880km/h relative to the air. It is flying from Denver, Colorado due west to Reno, Neveda, a distance of 1200km and will then return. There is a steady 90km/h wind blowing to the east. What is the difference in flight time between the two legs of the trip?
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is this just out of curiosity or is it a real question. I live in reno Nevada so mabe I can help. MAYBE
Its a real question from my physics class that I've been struggling with for like an hour and a half. I know the original time without the wind blowing would be 1200/880 but I can't figure out what to do after that to include the wind.
Let's remember the basic distance formula:
d = vt
As we know, the distance for both flights is 1200 km.
1200 = v₁t₁
1200 = v₂t₂
The airplane cruises at 880 km/h with AND against a 90 km/h wind.
1200 = (880 - 90)t₁
1200 = (880 + 90)t₂
From there, you can find the times
t₁ = 120/79 ≈ 1.52 h
t₂ = 120/97 ≈ 1.24 h
Therefore, the difference between the flight times is
1.52 - 1.24 = 0.28 h
d = vt
As we know, the distance for both flights is 1200 km.
1200 = v₁t₁
1200 = v₂t₂
The airplane cruises at 880 km/h with AND against a 90 km/h wind.
1200 = (880 - 90)t₁
1200 = (880 + 90)t₂
From there, you can find the times
t₁ = 120/79 ≈ 1.52 h
t₂ = 120/97 ≈ 1.24 h
Therefore, the difference between the flight times is
1.52 - 1.24 = 0.28 h
Thank you so very much I was doing it right the entire time I was just not converting my answer back to minutes like it was asking! Greatly appreciate it!
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