Five times the smallest of three consecutive odd integers is ten more than twice the longest.
Let the middle integer be x.
then the three odd integers are x-2, x, x+2.
Five times the smallest = 5(x-2)
ten more than twice the longest= 2(x+2)+10
so
5(x-2) = 2(x+2) + 10
5x-10 = 2x+4 + 10
5x-2x = 4 + 10 + 10
3x = 24
x = 8
The three integers are 6,8 and 10.
You can solve the other problems in the same way. If you have difficulties, post what you have done.
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