Five times a number is divided by 7 more than the number. If the result is 0, then what was the original number?

Answer 1

Let's call the original number "x".

According to the problem, "Five times a number" (5x) "is divided by 7 more than the number" (x+7). So we can write the equation:

5x ÷ (x+7) = 0

If we multiply both sides by (x+7), we can get rid of the fraction:

5x = 0(x+7)

Simplifying, we get:

5x = 0

This means that x must be 0, because any other number multiplied by 5 would not equal 0.

Therefore, the original number was 0.