First, understand the problem. Then translate the statement into an inequality.

Question

the perimeter
of the rectangle
is less than or equal to
110
↓
↓
↓
x+35+
x plus 35
x+35
less than or equals
≤
110

Part 3
Simplify the left side of the inequality.
x+35+x+35
≤
110
2 x plus 70
2x+70
≤
110
​(Simplify your answer. Do not​ factor.)

Part 4
Apply the addition property of inequality.
2x+70
≤
110
2x
≤
enter your response here

​(Simplify your​ answer.)

Answer 1

2x + 70 ≤ 110
Subtract 70 from both sides:
2x ≤ 40
Divide both sides by 2:
x ≤ 20

Answer 2

First, understand the problem. Then translate the statement into an inequality.
the perimeter
of the rectangle
is less than or equal to
110
↓
↓
↓
x+35+
x plus 35
x+35
less than or equals
≤
110

Part 3
Simplify the left side of the inequality.
x+35+x+35
≤
110
2 x plus 70
2x+70
≤
110
​(Simplify your answer. Do not​ factor.)

Part 4
Apply the addition property of inequality.
2x+70
≤
110
2x
≤
40
40

​(Simplify your​ answer.)

Part 5
​Next, apply the multiplication property of​ inequality,
2x
≤
40
x
≤
enter your response here

​(Simplify your​ answer.)

Answer 3

2x ≤ 40
Divide both sides by 2:
x ≤ 20

Answer 4

​​First, understand the problem. Then translate the statement into an inequality.
the perimeter
of the rectangle
is less than or equal to
110
↓
↓
↓
x+35+
x plus 35
x+35
less than or equals
≤
110

Part 3
Simplify the left side of the inequality.
x+35+x+35
≤
110
2 x plus 70
2x+70
≤
110
​(Simplify your answer. Do not​ factor.)

Part 4
Apply the addition property of inequality.
2x+70
≤
110
2x
≤
40
40

​(Simplify your​ answer.)

Part 5
​Next, apply the multiplication property of​ inequality,
2x
≤
40
x
≤
20
20

​(Simplify your​ answer.)

Part 6
​Finally, interpret the result.
The maximum width of a rectangle with a perimeter no greater than
110 centimeters and a length of
35 centimeters is
enter your response here
centimeters.

Answer 5

The maximum width of a rectangle with a perimeter no greater than 110 centimeters and a length of 35 centimeters is 20 centimeters.