Asked by shanere
fine the area bounded by the graphs of y=5x^2, y=20
5 x^2 = 20 --->
x =+/-2
Area is F(2) - F(-2)
where F(x) = 20x - 5/3 x^3
5 x^2 = 20 --->
x =+/-2
Area is F(2) - F(-2)
where F(x) = 20x - 5/3 x^3
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