Asked by Anonymous
what is the area bounded by x axis, x =2 and y^2 = 8x?
Answers
Answered by
Reiny
area = [integral] (8x)^(1/2) dx from 0 to 2
= (1/12)(8x)^(3/2) | from 0 to 2
= (1/12)(16)^(3/2) - 0
= 64/12
= 16/3
= (1/12)(8x)^(3/2) | from 0 to 2
= (1/12)(16)^(3/2) - 0
= 64/12
= 16/3
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