Finde three consecutive integers such that the sum of the first and third is 16

Answer 1

a = first integer

a + 1 = second integer

a + 2 = third integer

first integer + third integer:

a + a + 2 = 16

2 a + 2 = 16 Subtract 2 to both sides

2 a + 2 - 2 = 16 - 2

2 a = 14 Divide both sides by 2

a = 14 / 2 = 7

Three consecutive integers are 7, 8 , 9

7 + 9 = 16